A long rod, insulated to prevent heat loss along its sides, is in perfect therma

Question

A long rod, insulated to prevent heat loss along its sides, is in perfect thermal contact with boiling water (at atmospheric pressure) at one end and with an ice-water mixture at the other (Figure 1) . The rod consists of 1.00-m section of copper (one end in steam) joined end-to-end to a length L2 of steel (one end in ice). Both sections of the rod have cross-section areas of 4.00 cm2. The temperature of the copper-steel junction is 65.0 ?C after a steady state has been set up.

Part A

How much heat per second flows from the steam bath to the ice-water mixture?

Part B

Explanation / Answer

(1) The heat traveling through the copper rod = K*A*dT/l = 385*0.0004*(100-65)/1 = 5.39 W.

(2) Heat will travel through the steel at the same rate.
50.2*0.0004*65/L2 = 385*0.0004*35/1
50.2*65/L2= 385*35
50.2*65/385*35 = L2
L2 = 0.242 m

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