Two small spheres (of mass m) are connected by a mass less rod. Forces (F) are a

Question

Two small spheres (of mass m) are connected by a mass less rod. Forces (F) are applied to the spheres, causing the object to rotate about its centre, with ail angular acceleration. If the length of the rod increases, how must the applied force vary with the length in order to maintain a constant angular acceleration? An object is able to rotate about a pivot, indicated by the black dot. If three forces arc applied as shown with each small square having side length l.Ommd if forces are: F_1 - 5 N. F_2 - 8 N and F, - 5 N. and 0-30® which is the correct ranking from largest to smallest of the magnitude of the torque (t,. each force produces?

Explanation / Answer

10) Suppose the length of the rod is L then the torque applied by the force will be:

torque = F*L

Since torque = Moment of inertia times the angular acceleration.

As angular acceleration is constant here and moment of intertia is also constant hence torque must be constant. Hence F*L = constant

So option C is correct.

11) Torque due to force F1 = 5*3 = 15 Nm

Torque due to force F2 = 8*3 sin(30) = 12 Nm

Torque due to Force F3 = 5*1 = 5 Nm

Then ranking will be t1> t2>t3

Option B is correct.

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