The two wires shown in the figure below carry currents of I = 5.76 A in opposite
ID: 1589199 • Letter: T
Question
The two wires shown in the figure below carry currents of I = 5.76 A in opposite directions and are separated by d0 = 8.95 cm. (Figure Included Here) Calculate the net magnetic field at a point midway between the wires. Use the direction into the page as the positive direction and out of the page as the negative direction. 5.15×10-5 T You are correct. Your receipt no. is 161-5857 Help: Receipt Previous Tries Calculate the net magnetic field at point P1 - that is, d1 = 9.25 cm to the right of the wire on the right. Remember to use the direction into the page as the positive direction and out of the page as the negative direction. As well, don't forget right-hand rule 2. Incorrect. Tries 2/10 Previous Tries Calculate the net magnetic field at point P2 - that is, d2 = 20.9 cm to the left of the wire on the left.
Explanation / Answer
B=uI/2piR
for point P1, B= B due too both wires
=uI /[2pi(0.0895+0.0925)] - uI /[2pi(0.0925)]
=uI / [2pi*0.182] - uI /[2pi(0.0925)] now lets put value of u,
=0.00000633 - 0.00001245 = -6.12 * 10-6 T
for point P2, B= B due too both wires
=-uI /[2pi(0.209)] + uI /[2pi(0.2985)]
= -0.00000551 + 0.00000386
= -1.65 *10-6 T
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.