Two small plastic spheres are given positive electrical charges. When they are 1
ID: 1589945 • Letter: T
Question
Two small plastic spheres are given positive electrical charges. When they are 12.0 cm apart, the repulsive force between them has magnitude 0.200 N .
A) What is the charge on each sphere if the two charges are equal?
B) What is the charge on each sphere if one sphere has four times the charge of the other?
**Show Work Please
Problem 17.14 Part A Two small plastic spheres are given positive electrical charges. When they are 12.0 cm apart the repulsive force between them has magnitude 0.200 N What is the charge on each sphere if the two charges are equal? Submit My Answers Give Up Part B What is the charge on each sphere if one sphere has four times the charge of the other? AXp ? Q1, Q2= Submit My Answers Give UpExplanation / Answer
One Charge = q1 = q
Other charge = q2 =q
Force = F = 0.2 N
Distance = r = 12 cm = 0.12 m
permittivity of free space = eo =8.854×1012 C^2/ (N.m^2)
k = 8.99*10^9 N.m^2/C^2
Using Coulomb's law,
F=kq1q2/r^2
F = kq^2/r^2
q^2 =F*r^2/k
q = sqrt[0.2*(0.12^2)/(8.99*10^9)]
q =0.566*10^-6 C
Each charge is 5.66*10^-7 C
B)
One Charge = q1 = q
Other charge = q2 =4q1 = 4q
q1q2 =F*r^2/k
(q)(4q) = F*r^2/k
q = sqrt(0.2*(0.12^2)/(4*8.99*10^9))
q = 0.283*10^-6 C
Therefore,charge on first sphere =4 q = 4*2.83*10^-7 C = 1.132*10^-6 C
If the charge on first sphere is four times the charge of the other, then charge on first sphere is 1.3824*10^-6 C and charge on the second sphere is 2.83*10^-7 C
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