I need help with number 6 3) The position x, in meters, of an object is given by

Question

I need help with number 6 3) The position x, in meters, of an object is given by e equation x seconds. What are the si units of A, B, and C? ty of RA A Bt C2, where vevweserws. 4) A motorist makes a trip of 180 miles. For the first miles drives at a constant speed or mph. At what constant speed remaining distanc if her average speed for the total trip is to be 40 mph? must she drive the 5) An object is thrown upwards with a speed of 13 long does it take to reach a height of 4.0 m above the projection poin while descending? Neglect air resistance. 12.3 sl 6) A foul ball is hit straight up into the air with a speed of 30 m/s, and air resistance is negligible (a) Calculate the time required for the ball to rise to its maximum height. (b) Calculate the maximum height reached by the ball above the point where it hit the bat. (c) Determine the times at which the ball passes a point m above the point where it was hit by the bat 25 m (d) Explain why the are two answers to part (c). 3.1 s (b) 46 m (c) 1.0 s and 5.1 s (d) One value for the ball traveling up one value for the ball traveling downward.] 7) A train starts from rest and accelerates uniformly until it has traveled s 6 km and acquired a forward velocity of 2 m/s. The train then moves at a constant velocity of 42 m/s for 420 s. The train then slows down uniformly a a 5 m/s2, until it is brought to a halt. The acceleration during the first 5.6 km of travel is closest to which of th ng Displacement vector A is 75 cm long and points at 30° above the +x-axis. Displacement vector is and points along the Displacement vector long and points at 45° below the -x-ax is 40 cm Determine the x and y components of vector A. Determine the r and y components of vector H etermine the r and y components of vector C termine the r and y components of the resultant of these three vectors. ermine the magnitude and direction of the resultant of these three vectors. gure shows two vectors is and C, along with their magnitudes and directions.

Explanation / Answer

6)

(a)
Initial Velocity, u = 30 m/s
Acceleration, a = 9.8 m/s^2
Final Velocity , V = 0 (At max height.)

Let the Time taken to raech max Height, = t

v = u - a*t
t = 30/9.8 s
t = 3.1 s
Time taken to reach max height, t = 3.1 s

(b)
Max Height reached, S
V^2 = u^2 - 2*a*S
0 =30^2 - 2*9.8*S
S = 45.9 m
Max Height reached, S = 45.9 m

(c)
It passes 25 m point two times, once while going up & once while coming down.

(d)
S = u*t + 1/2 at^2
25 = 30*t - 1/2*9.8*t^2
t = 1.0 & 5.1 s
Time at which it crosses the 25 m Point, t = 1.0 & 5.1 s

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