Using the capacitor simulation found here (http://phet.colorado.edu/en/simulatio

Question

Using the capacitor simulation found here (http://phet.colorado.edu/en/simulation/capacitor-lab), I really just need help with understanding what I am observing.

Set voltage to 1.5V, set plate separation to 5mm and disconnect the battery. Make the Stored Energy meter viewable.

a) What changes do you observe when you increase the plate separation? PREDICT why this happens

b) Where does this energy go (or come from)?

Repeat with the battery connected

c) What changes do you observe in regards to stored energy when you increase the plate separation? Predict why this happens.

d) Where does this energy go (or come from)?

View 10 13 10 12 10 12 Plate Charges Electric Field 9 Meters_ Capacitance Plate Charge Stored Energy Voltmeter Electric Field Disconnect Battery Capacitance 0.89x10-13 F Plate Charge (top) 0.13x1012 c Stored Energy 0.10x1012) Separation 10.0 mm Res Plate Area 100.0 mm 4tt 1.5 v Electric Field Plate

Explanation / Answer

a) charge remainse same on the capacitor.

when plate separation increases capacitance decreses.

so, potentail difference between the lates increases

Energy stored also increases.

U = q^2/(2*C)

b) The increased energy come from workdone by external egent on separting the plates.

c) the energy stored decreases.

because voltage across the capacitor remainse same but capacitnace decreases.

U = 0.5*C*V^2

d) This energy is converted to thermal energy.

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