The figure above shows four very thin parallel planes of charge with equal separ

Question

The figure above shows four very thin parallel planes of charge with equal separation between them. The charge density on plate 1 is -2 ?. The charge density on plate 2 is 3 ?. The charge density on plate 3 is -5 ?. The charge density on plate 4 is 1 ?. Your answers for the electric field must include the correct sign. We choose positive electric field along the positive x-direction.

What is the Electric Field at point E? (in units of ?/?0)

I really don't understand when the values should be divided by -2 or just 2, can you also explain that?

1 2 3 4 The figure above shows four very thin parallel planes of charge with equal separation between them. The charge density on plate 1 is-2 The charge density on plate 2 is 3 . The charge density on plate 3 is-5 . The charge density on plate 4 is 1 . Your answers for the electric field must include the correct sign. We choose positive electric field along the positive x-direction.

Explanation / Answer

electirc field due to each plane is E = /20

is the surface charge density

0 is the permittivity of free space

due to plane1 is E1 = -2/20

due to plane2 is E2 = 3/20

due to plane3 is E3 = -5/20

due to plane4 is E4 = /20

then Electric field at point E is E = E1+E2+E3+E4

E = ( -2/20)+(3/20)-(5/20)+(/20) = -1.5(/0)

E = 1.5(/0) towards plane 4

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