The figure (Figure 1) shows cross sections of five closed surfaces S 1, S 2, etc
ID: 2284074 • Letter: T
Question
The figure (Figure 1) shows cross sections of five closedsurfaces S1, S2, etc. Assume that q1 = 5.4?C , q2 = 8.6?C , q3 = 1.1?C , q4 = 7.6?C , q5 = 7.2?C , and q6 = 10.4?C .
Part A
Find the net electric flux passing through the surface S1.
Express your answer using two significant figures.
0
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Correct
Part B
Find the net electric flux passing through the surface S2.
Express your answer using two significant figures.
8.85
The figure (Figure 1) shows cross sections of five closedsurfaces S1, S2, etc. Assume that q1 = 5.4?C , q2 = 8.6?C , q3 = 1.1?C , q4 = 7.6?C , q5 = 7.2?C , and q6 = 10.4?C .
Part A
Find the net electric flux passing through the surface S1.
Express your answer using two significant figures.
? =0
N?m2/CSubmitMy AnswersGive Up
Correct
Part B
Find the net electric flux passing through the surface S2.
Express your answer using two significant figures.
? =8.85
Explanation / Answer
Let's solve all five parts at the same time.
Net electric flux of a closed surface is, by Guass's law, equivalent to the charge that surface encloses divided by the permittivity of free space, e_0. Therefore, all you have to do to calculate flux is
Flux = Charge enclosed / 8.85 x 10^(-12)
A. q in S1 = 0
flux = 0
B. q in S2 = q1 + q2 - q5 = 14 - 7.2 = 6.8
flux = 6.8*10^-6/8.85*10^-12
C. q in S3 = q2 + q3 - q6 = 9.7 - 10.4 = -0.7
flux = -0.7*10^-6 / 8.85*10^-12
D. q in S4 = 7.4 - 7.2 = 0.2
flux = 0.2*10^-6 / 8.85*10^-12
E. q in S5 = 22.7- 17.6 = 5.1
flux = 5.1*10^-6 / 8.85*10^-12
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