While watching a softball game you see a play that makes you wonder how fast a f

Question

While watching a softball game you see a play that makes you wonder how fast a fielder can react to a hit, run to the fence, and leap up to make the catch. In this play, the batter hits a ball when it is barely off the ground. It looks like it will be home run over the left center field wall which is in a distance D= 205.0 ft from home plate. As soon as the ball is hit, the left fielder runs to the wall, leaps high, and catches it just before it clears the top of the wall with height h= 10.0 ft . You estimate that the ball left the bat at an angle of =30°.

Need answer in si units

Explanation / Answer

The base ball leaves the bat at velocity 'V' at an angle 30 degree with horizontal at the level at which it left the bat.

So there will be two components of 'V'
1.) Vertical component =V1 = V sin 30m/s
2.) Horizontal Component=V2= V cos30 m/s

Note: the Horizontal component:V2 will be always Constant as there is no acceleration/deceleration towards horizontal movement.

Given v2 sin2theta/g = 205

v=48.18 m.s

The vertical Component will take the ball to a height vertically.

Initial velocity of Ball vertically=vsin30
h=10m, a= -g= -9.8m/s^2

h=vt+1/2 at^2
10=vsin30t-4.9t^2
4.9t^2+10-24.09t=0

t = 0.457 seconds

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