QUESTION 1 In part 1 of today\'s experiment (no incline), if the mass on the han

Question

QUESTION 1

In part 1 of today's experiment (no incline), if the mass on the hanger was measured to be 55 grams, and the mass of the cart (weights included) was measured to be 510 grams, what would the theoretical acceleration (in m/s2) of the cart be? (assume g=9.8 m/s2)

QUESTION 2

In part 2 of today's experiment, if the mass on the hanger was measured to be 90 grams, the mass of the cart (weights included) was measured to be 567 grams, and the angle of the incline is 6o what would the theoretical acceleration (in m/s2) of the cart be? (assume g=9.8 m/s2)

2 points   

QUESTION 3

In part 1 of today's acceleration experiment,the acceleration of the system would ________, if we added more weight to the cart without changing the mass of the hanger.

stay the same

decrease

increase

1 points   

QUESTION 4

In part 1 of today's acceleration experiment,the acceleration of the system would ________, if we added more weight to the hanger without changing the mass of the cart.

stay the same

decrease

increase

1 points   

QUESTION 5

In part 1 of the acceleration experiment, what would happen if the masses of the hanger was exactly equal to the mass of the cart?

The hanger would accelerate upward.

The system would move at a constant velocity.

The hanger would accelerate downward.

The system wouldn't move.

1 points   

QUESTION 6

You tie one end of a massless string to a tree and exert a force of 163N to the other end. What is the tension (in N) in the string?

1 points   

QUESTION 7

Tom and Bob pull a massless string. They exert the same force of 36N to both ends of the string. What is the tension (in N) of the string at the middle of the string?

1 points   

QUESTION 8

A 19 kg box is pushed accross a frictionless table with a constant force of 48N, what is the acceleration of the box (in m/s2)?

Please I need anwers ASAP! Thanks

Explanation / Answer

Q6)

tension = 163 N

Q7)

tension at the middle = 0

Q8)

acceleration = F/m = 48/19 = 2.53 m/s^2

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