At time t = 0 s, automobile A is traveling at a speed of 20.0 m/s along a straig

Question

At time t = 0 s, automobile A is traveling at a speed of 20.0 m/s along a straight road and is picking up speed with an acceleration that has a magnitude of 3.60 m/s2 as in part a of the figure. At t = 0 s, automobile B is traveling at a speed of 20.0 m/s in uniform circular motion as it negotiates a turn (part b of the figure). It has a centripetal acceleration whose magnitude is also 3.60 m/s2. Determine the speed of (a) automobile A and (b) automobile B, when t = 2.0 s

I don't understand the steps to get to the final answer.

Explanation / Answer

a)

For automobile A

Vi = initial Speed = 20 m/s

Vf = final Speed= ?

a = acceleration = 3.60 m/s2

t = time = 2 sec

using the equation

Vf = Vi + a t

Vf = 20 + 3.6 x 2

Vf = 27.2 m/s

B)

In Uniform circular motion , the speed remains same hence V at t = 2 = 20 m/s

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