A capacitor is connected in the circuit shown with two resistors, R_A and R_B. E
ID: 1594339 • Letter: A
Question
A capacitor is connected in the circuit shown with two resistors, R_A and R_B. Each resistor has a resistance R. The emf of the battery, which has negligible internal resistance, is 6 V. The capacitor is initially uncharged. After the switch is closed, the capacitor voltage eventually levels off at what value? When the switch is closed, which statement best reflects what happens to the current through resistor B, the one in parallel with the capacitor? The current increases from zero, and eventually reaches a value of the battery voltage divided by 2_R. After the switch is closed, the current oscillates because the capacitor cycles continually from charging to discharging and back. The current increases from zero, and eventually reaches a value of the battery voltage divided by R. As soon as the switch is closed, the current jumps to a particular value and is constant after that. As soon as the switch is closed, the current jumps to a particular value and then it decreases exponentially to zero.Explanation / Answer
A) voltage will be equal to voltage accross RB = 3 V answer
B) first option. The current increases from zero and eventually reaches a value of the battery voltage divided by 2R
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