help please!! Two charge q_1 = +5 times 10^-9 C and q^2 = +B times 10^-9 C are p

Question

help please!!

Two charge q_1 = +5 times 10^-9 C and q^2 = +B times 10^-9 C are placed 40.0 cm apart. A third = 5 times 10^9 C is placed between the two particles at a distance r = 31 cm from q_1 in the diagram below. Determine the net force on the q_3 due to the combined of q_1 and q_2 Three charges, Q1 = +4.0 nC, Q2 = - 4.0 nC and a test charge Qo = - 8 nC are placed at the corners of an isosceles triangle as shown in the diagram above. Qo lies along the x axis midway between Q1 and Q2. The distance R = 0.21 m and the angle theta = 31degree Calculate the total force on the test charge Qo

Explanation / Answer

q1 = 5*10^-9 C, q2 = 8*10^-9 C, q3 = -5*10^-9 C

F = kq1q2/r^2

F3 = F31 +F32

F3 = -(9*10^9*5*10^-9*5*10^-9/0.31^2) + (9*10^9*5*10^-9*8*10^-9/0.09^2)

F3 = 4.21*10^-5 N

correct option is (A)

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