Question
help please!!
Use the exact values you enter in previous answer(s) to make later calculation(s). The kick experienced when firing a rifle can be explained by Newton's third law. A .22-caliber rifle has a mass M = 5.1 kg, and a bullet with a mass m = 3.0 g leaves the barrel of the gun at a velocity of 350 m/s. If the bullet starts from rest and leaves the gun barrel after t = 0.010 s, what was the acceleration of the bullet, at, ? Assume the bullet's acceleration is constant while it travels along the barrel. ab = 35000 m/s2 What was the force on the bullet? (Enter the magnitude only.) X N What was the magnitude of the force exerted on the gun? X N What acceleration, ar, did the gun experience? (Assume the bullet is traveling in the positive direction. Indicate the direction with the sign of your answer.) ar = X m/s2 Compare the ratio of M and m to the ratio of the accelerations of each object. M/m = ab/ar =
Explanation / Answer
a) v = u +at
=> 350 = 0 +a*0.01
=> a = 35000 m/s^2
b)F = ma = 35000*3/1000 = 105 N
c) force on gun = force on bullet = 105 N
d) a = F/M = 105/5.1 = 20.5882352941176471 m/s^2
e)M/m = 1700
ab/ar = 1700
