In the circuit below, V B A T = 16 V. Part A What is the equivalent capacitance

Question

In the circuit below, VBAT= 16 V.

Part A What is the equivalent capacitance for the combination of the 6 and 3 F capacitors?

Part B What is the equivalent capacitance for the entire circuit?

Part C How much charge does the battery supply?

Part D What is the charge on the 6 F capacitor?

Part E What is the voltage across the 6 F capacitor?

Part F What is the voltage across the 3 F capacitor?

Part G What is the charge on the 2F capacitor?

Part H What is the total energy stored by the capacitors?

J

Explanation / Answer

C1 = 2 UF

C2 = 6 uF

C3 = 3 uF

part(A)

C2 and C3 are in series

C23 = (C2*C3)/(C2+C3)

C23 = (6*3)/(6+3) = 2 uF <<<<<=============answer

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part(B)

Ceq = C1 + C23

Ceq = 2 + 2 = 4 F <<<<--------answer

-----------

part(C)

charge supplied by battery Q = Ceq*V = 4*16 =64 uC <<<<---answer

=========

part(D)

Q2 = C23*V = 2*16 = 32 uC <<<<------------answer

===================

part E

voltage across C2 , V2 = Q2/C2 = 32/6 = 5.33 V <<<<--------answer

===============

part(F)

V3 = V - V2 = 16 - 5.33 =10.67 V

==================

part(G)

V1 = V = 16 v

==============

part(H)

total energy U = (1/2)*Ceq*V^2 = (1/2)*4*10^-6*(16)^2 = 512*10^-6 J <<<--------answer

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