A person on a diet loses 2.6 kg in a week. How many micrograms/second (mu g/s) a
ID: 1600576 • Letter: A
Question
A person on a diet loses 2.6 kg in a week. How many micrograms/second (mu g/s) are lost? A) 3.6 times 10^3 mu g/s B) 4.1 times 10^3 mu g/s C) 4.3 times 10^3 mu g/s D) 4.6 times 10^3 mu g/s E) 2.6 times 10^3 mu g/s Let A vector = 2 i vector + 6 j vector - 3 k vector and B vector = 4 i vector + 2 j vector + 4 k vector, Then A vector middot B vector equals: A) 8 i vector + 12 j vector - 12 k vector B) 14 C) 11 D) 8 E) 5 What is the vector product A vector times B vector of A vector = 2 i vector + 3 j vector + 1 k vector and B vector = 1 i vector - 3 j vector - 5 k vector? A) - 15 + 13 j vector - 9 k vector B) - 3 i vector + 5 j vector - 9 k vector C) - 6 i vector + 7 j vector - 9 k vector D) - 9 i vector + 9 j vector - 9 k vector E) - 12 i vector + 11 j vector - 9 k vector A car accelerates from 10.0 m/s to 30.0 m/s at a rate of 6.00 m/s^2. How far does the car travel while accelerating? A) 66.7 m B) 57.1 m C) 133 m D) 100 m E) 80.0 mExplanation / Answer
1) 2.6 kg/week
= 2.6*10^9 / 7*24*60*60
= 4.3*10^3 ug/s
2) A.B = (2)(4) + (6)(2) +(-3*4)
= 8
3) A X B = [ i j k]
[2 3 1]
[1 -3 -5]
= i ( -15 +3) - j(-10 - 1) + k(-6-3)
= -12i +11j -9k
4) v^2 - u^2 = 2aS
30^2 - 10^2 = 2*6*S
S = 66.7 m
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