The total magnetic field anomaly for a buried cylinder as measured at the surfac

Question

The total magnetic field anomaly for a buried cylinder as measured at the surface directly above it is

T= (pie)(k)(H)(R/d)^2

R=2.5 cm

d=2m

Where T is the anomaly, H is the Earth's magnetic field, R is the cylinder's radius, d is the depth to the top of the cylinder and k is susceptibility.

1. Assuming a soil susceptibilty of 10^-4 and one for steel of 63, calcualte the magnetic anomaly directly above the cyliner.

2. Now take the cyliner to be just air with k(air)=10^-6 (no steel walls) and re-calculate the anomaly.

3. If the magnetometer can detect only anomalies greater than 10^-9 Tesla, how large would the radius of the air-filled cylinder have to be to produce a detectable anomaly?

Please Help!!

Explanation / Answer

The total magnetic field anomaly for a buried cylinder as measured at the surfac

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