A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling hor

Question

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 55.0 m/s, and it leaves the bat traveling to the left at an angle of 30 degree above horizontal with a speed of 60.0 m/s. The ball and bat are in contact for 1.85 ms. Find the horizontal component of the average force on the ball Take the x-direction to be positive to the right F_x = Express your answer using two significant figures. Find the vertical component of the average force on the ball. F_y = Express your answer using two significant figures.

Explanation / Answer

Part A

To calculate the horizontal componentWe need to calculate horizontal impulse

=m*(Vf-Vi)

=0.145*(-60*cos(30)-55)

=0.145*(-51.9-55)

=-15.5005kgm/s

horizontal component =Change in momemtum/Change in time

=-15.5005/0.00185

=-8378.648N

horizontal component of force= -8378.648N to the left

PartB

TO calculate the vertical component of average force

=m*(Vf-Vi)

=0.145*(60*sin(30)-0)

=0.145(60*1/2)

=4.35

Vertical component of force = Change in momentum/Change in time

=4.35/0.00185

=2351.35135N

Vertical component of force =2351.35N to tht top

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.