Homework 7 Begin Date: 3/12/2017 7:00:00 AM Due Date: 3/27/2017 11:59:00 PM End
ID: 1602762 • Letter: H
Question
Homework 7 Begin Date: 3/12/2017 7:00:00 AM Due Date: 3/27/2017 11:59:00 PM End Date: 3/27/2017 11:59:00 PM (8%) Problem 12: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (left lens) and 21 37.5 cm (right lens) are separated by a distance cm. Otheexpertta.com 13% Part (a) If an object is placed a distance do fi to the left of the first lens (the left lens), will the resulting image from the first lens be real or virtual, and inverted or upright? A 13% Part (b) If a 3.3 cm tall object is placed as indicated in part (a), and the image formed 0.63 cm tall, what is the magnification of the is first lens? A 13% Part (c) Using the information from part (b), calculate the image distance, in centimeters, from the first lens Grade Summary Deductions Potential 100% sino cos0 tan0 Submissions It 7 8 9 Attempts remaining: 15 cotano asino acos0 5 6 (09 per attempt) detailed view atan0 acotan0 si 1 2 3 cosh0 tanh0 cotanh0 vo Degrees Radians BACKSPACE Submit Hint Hints: SG deduction per hint. Hints remaining Feedback: 5% deduction per feedback. 13% Part (do Does the image formed by the first lens serve as a real or a virtual object for the second lens? A 13% Part (e) What is the image distance, in centimeters, for the second lens? A 13% Part (f What is the magnification of the second lens? A 13% Part (g What is the total magnification of this compound optical system? 13% Part (h) Is the image created by the second lens real or virtual? Is it upright or inverted?Explanation / Answer
a) the resulting image will be real and inverted
b) magnification = height of image / height of object
magnification = 0.63 / 3.3
magnification = 0.1909
c) magnification = -distance of image / distance of object
0.1909 = -distance of image / distance of object
by lens equation
1 / f = 1 / u + 1 / v
1 / 7.5 = 1 / distance of image + 1 / (-distance of image / 0.1909)
distance of image = 6.068 cm
d) image formed by first lens will act as virtual object for second lens
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