Find the heat lost by the water, calorimeter cup (c = 0.21) , and stirrer ( c =
ID: 1603838 • Letter: F
Question
Find the heat lost by the water, calorimeter cup (c = 0.21) , and stirrer ( c = 0.11). Use the formula Q=mcdeltaT
Once the ice has melted it becomes cold water at 0 degrees celcius. Calculate the heat it absorbs to raise its temperature to the final equilibrium temperature (use same equation)
VALUES:
Dry calorimeter cup: 60.9 g
-cup with water = 161.8g
stirrer alone = 30.4 g
Temperature of cup = 20.6 degrees celcius
The temperature it dropped too after stirring in ice = 11.61 degrees celcius
after experiment: The cup with water and stirrer = 205.9g
-after experiment: Cup with just water = 175.7g
Explanation / Answer
heat lost = m*C*dT
heat lost by calorimeter = mcalorimeter*C*dT = 60.9*0.21*(20.6-11.61) = 114.97311 J
heat lost by water = mwater*C*dT = (161.8-60.9)*1*(20.6-11.61) = 907.091 J
heat lost by stirrer = mstirrer*C*dT = 30.4*0.11*(20.6-11.61) = 30.1 J
total heat lost = 114.97311 + 907.091 + 30.1 = 1052.16411 J
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