In order to increase resistance, a person puts two exercise cords together. A pe

Question

In order to increase resistance, a person puts two exercise cords together. A person pulls one cord with a force probe that exerts a 50-N force on the cord, causing it to stretch 19cm. What is the effective spring constant of the two bands compared to one.

*******Can someone please explain to me what I am doing wrong? I determined the spring constant was 2 and to solve......50N/.19m and got 263.2N/m then I divided that by the spring constant (263.2N/m/2)=131.6 N/m which was an incorrect answer. I then tried to plug in the 263.2 N/m which was also incorrect.*********Please show work so I can understand what I am doing wrong

Explanation / Answer

Here the two cords are in series so

the spring constant of two cords will be half of the one cord

=> Kef = K/2

here K = 50/0.19 = 263.16 N/m

so Kef = K/2 = 263.16/2 = 131.57 = 1.3*102 N/m

(Take care of significant number also)

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