A 0.22 kg stone is held 1.1 m above the top edge of a water well and then droppe

Question

A 0.22 kg stone is held 1.1 m above the top edge of a water well and then dropped into it. The well has a depth of 5.6 m. (a) Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone-Earth system before the stone is released? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. J (b) Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone-Earth system when it reaches the bottom of the well? 12.32 The response you submitted has the wrong sign. J (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well? J

Explanation / Answer

part a )

U = mgh

before release

h = 1.1

U = 0.22 * 9.8 * 1.1 = 2.371 J

part b )

after release

h = -5.6m

=0.22*9.8*-5.6

U = -12.07 m

part c )

dE = E2-E1 = -12.07- 2.371= 14.441 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.