After landing on an unfamiliar planet, a space explorer constructs a simple pend

Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 50.0 cm . She finds that the pendulum makes 110 complete swings in a time of 145 s .

Part A

What is the value of g on this planet?

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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 50.0 cm . She finds that the pendulum makes 110 complete swings in a time of 145 s .

Part A

What is the value of g on this planet?

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Explanation / Answer

The period of a pendulum is given by T = 2sqrt(L/g). Since this is a different planet, g will be different, so we can use the above formula to solve for it. Start by calculating the period, T, the time it takes for one swing:

T = 145 s/110 swings
T = 1.318

Now solve for g (L needs to be in meters, so divide 50.0 by 100):

T = 2sqrt(L/g)
1.318 = 6.28sqrt(0.5/g)
0.2098 = sqrt(0.5/g)
0.044 = 0.5/g
g = 0.5/0.044

g = 11.4 m/s2

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