After landing on an unfamiliar planet, a space explorerconstructs a simple pendu

Question

After landing on an unfamiliar planet, a space explorerconstructs a simple pendulum of length 53.0 cm. The explorerfinds that the pendulum completes 104 full swing cycles in a timeof 137 s. What is the value of the acceleration ofgravity on this planet? After landing on an unfamiliar planet, a space explorerconstructs a simple pendulum of length 53.0 cm. The explorerfinds that the pendulum completes 104 full swing cycles in a timeof 137 s. What is the value of the acceleration ofgravity on this planet? What is the value of the acceleration ofgravity on this planet?

Explanation / Answer

the equation for a pendulum is: T=2*(L/g) the period T is 137/104=1.32 seconds. so we have 1.32=2*(.53/g) g=12.0 m/s2

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