A 1300 -kg car is pushing an out-of-gear 2100 -kg truck that has a dead battery.

Question

A 1300 -kg car is pushing an out-of-gear 2100 -kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push horizontally against the ground with a force of 4570 N . The rolling friction of the car can be neglected, but the heavier truck has a rolling friction of 770 N , including the "friction" of turning the truck's drivetrain. What is the magnitude of the force the car applies to the truck?

Part C

What is the magnitude FConT of the force that the car exerts on the truck? Use the coordinate system shown in Part B, where upward is the positive y direction and to the right, the direction FConT points, is the positive x direction.

PSS 7.1 Interacting-Objects Problems Learning Goal: To practice Problem-Solving Strategy 7.1 for interacting-objects problems. A 1300 -kg car is pushing an out-of-gear 2100-kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push horizontally against the ground with a force of 4570 N. The rolling friction of the car can be neglected, but the heavier truck has a rolling friction of 770 N including the "friction" of turning the truck's drivetrain. What is the magnitude of the force the car applies to the truck? Part C What is the magnitude conT of the force that the car exerts on the truck? Use the coordinate system shown in Part B, where upward is the positive y direction and to the right, the direction F points, is the positive x conT direction Express your answer in newtons to three significant figures. F ConT

Explanation / Answer

acceleration of the system= F/M

(m+m)a = f

(1300+2100)a= 4570-770

a= 1.1176 m/s^2

Force exerted by car on truck = ma + 770

FconT = 2100*1.11 +770

FconT = 3117.05 N

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