A mirror has a focal length -20 cm. f an object is placed 10 cm in front of the

Question

A mirror has a focal length -20 cm. f an object is placed 10 cm in front of the mirror, where will the image form? 20 cm in front of the mirror 20 cm behind the mirror 6.7 in from of the mirror 6.7 behind the mirror no image will form A thin lens of focal length -12.5 cm has a 5.0 cm tall object placed 10 cm in front of it. Where is the image located? 2.5 cm behind the lens 5.6 cm behind the lens 5.6 cm in front of the lens 50 cm behind the lens 50 cm in front of the lens A thin lens of focal length -12.5 cm has a 5.0 cm tall object placed 10 cm in front of it. What are the size and orientation of the image? 4.0 cm, inverted 4.0 cm, upright 2.8 cm, inverted 2.8 cm, upright 100 cm inverted A thin lens of focal length 12.5 cm has a 5.0 cm tall object placed 10 cm in front of it. Where will the image be formed? 2.5 cm behind the lens 5.6 cm behind the lens 5.6 cm in front of the lens 50 cm behind the lens 50 cm in front of the lens A thin lens of focal length 12.5 cm has a 5.0 cm tall object placed 10 cm in front of it. What is the size and orientation of the image? 4.0 cm, inverted 4.0 cm, upright 8.9 cm inverted 8.9 cm, upright 25 cm, upright

Explanation / Answer

18)

f = focal length = - 12.5 cm

do = object distance = 10 cm

di = image distance

using the lens equation

1/f = 1/di + 1/do

1/(-12.5) = 1/di + 1/10

di = - 5.6 cm

ho = object height = 5 cm

hi = image height = ?

using the magnification equation

hi/ho = - di/do

hi/5 = - (-5.6)/10

hi = 2.8 cm

the image is inverted

19

f = focal length = 12.5 cm

do = object distance = 10 cm

di = image distance = ?

using the lens equation

1/f = 1/di + 1/do

1/(12.5) = 1/di + 1/10

di = 50 cm

behind the lens

20.

f = focal length = - 12.5 cm

do = object distance = 10 cm

di = image distance

using the lens equation

1/f = 1/di + 1/do

1/(12.5) = 1/di + 1/10

di = 50 cm

ho = object height = 5 cm

hi = image height = ?

using the magnification equation

hi/ho = - di/do

hi/5 = - (- 50)/10

hi = 25 cm

the image is upright

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