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A 4000 kg freight car rolls along rails with negligible friction. The car is bro

ID: 1605797 • Letter: A

Question

A 4000 kg freight car rolls along rails with negligible friction. The car is brought to rest by a combination of two coiled springs as illustrated in the figure below. Both springs are described by Hooke's law with k1 = 1500 N/m and k2 = 3600 N/m. After the first spring compresses a distance of 30.0 cm, the second spring acts with the first to increase the force as additional compression occurs as shown in the graph. The car comes to rest 55.0 cm after first contacting the two-spring system. Find the car's initial speed.

Total force (N) klx1 x2 Distance (cm)

Explanation / Answer

work done during the x1 distance

w1 = 1/2k1x1^2 = 1/2*1500*0.55^2 = 226.9 J

The second spring is compressed only after the freight car moves a distance of 0.30 m, so it is only compressed a distance of x2 = 0.25 m

w1 = 1/2*3600*0.25^2 = 112.5 J

w tot = w1+w2 = 339.4 J

w = 1/2mv^2 = 339.4

v = 0.41 m/s

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