pool player hits a cue ball directly into the 8 ball. The cue ball is traveling
ID: 1606957 • Letter: P
Question
pool player hits a cue ball directly into the 8 ball. The cue ball is traveling at 5m/s before the collision and 2m/s in the opposite direction afterwards, If the 8-ball is initially at rest, how fast is it moving after the collision? Both balls have the same mass. pool player hits a cue ball directly into the 8 ball. The cue ball is traveling at 5m/s before the collision and 2m/s in the opposite direction afterwards, If the 8-ball is initially at rest, how fast is it moving after the collision? Both balls have the same mass.Explanation / Answer
m1u1 = m1v1+m2v2
As no external forces are applied we can use Conservation of linear momentum to solve this problem
m1=m2
v2=u1-v1
=5-(-2)=7m/s
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