Exercise 29.31 A 0.347 m long metal bar is pulled to the left by an applied forc
ID: 1607965 • Letter: E
Question
Exercise 29.31 A 0.347 m long metal bar is pulled to the left by an applied force F and moves to the left at a constant speed of 5.90 m/s. The bar rides on parallel metal rails connected through a 45.8 2 resistor, as shown in (Figure 1) so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.669 T magnetic field that is directed out of the plane of the figure. of 1 Figure 1 Part A Is the induced current in the circuit clockwise or counterclockwise? O clockwise O counterclockwise Submit My Answers Give Up Part B What is the rate at which the applied force is doing work on the bar? Express your answer with the appropriate units Value Units Submit My Answers Give Up Provide Feedback ContinueExplanation / Answer
a)
Counterclockwise
b)
= B * A ,
is the flux ,
A is area.
Emf = d/dt = B*dA/dt = 0.669 * 0.347 * 5.9
and P = Emf^2 / R
So,
P = ((0.669 * 0.347 * 5.9)^2)/45.8
=> P = 41mW
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