(5%) Problem 18: A turntable of radius 25 cm and rotational inertia ariable Desc
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(5%) Problem 18: A turntable of radius 25 cm and rotational inertia ariable Description 0.0154kg m is spinning freely at 22.0 rpm about its central axis, Turmtal with a 19.5g mouse on its outer edge. The mouse walks from the Turntable inertia edge to the center. Assume the turntable-mouse system is isolated, Initialsystem angular velocity 2m 630rad I and put your answers in terms of the variables listed. 19.5 initial system Final system rotabona inertia ar Final system angular velocity Work done Otheexpertta.com P A 17% Part (a) Treat the mouse as apoint-particle, and define the turntable's initial rotation direction to be positive. Calculate the system moment of inertia before the mouse moves Ibeer in terms of the variables above. Potential 100% I give up! leted Feedback: deduction per feedback Hints: deduction per hint. Hints remaining leted 17% Part o) Calculate the moment of inertia after the mouse moves to the center in terms of the variables above, above. 17% Part (e) Assume the systems system's final rotation speed in terms of the variables turntable-mouse system is isolated Find the 17% Part (n solve for the final rotational speed orin of the variables above. rt (e) Ignore friction within the turntable-mous Determine the work done by the mouse in terms 17% par dry what is the numerical value done in Joules? ie 17% mpletedExplanation / Answer
a] I before= Io +mR^2
b] Iafter = Io
c] wf = wo*Ibefore/Iafter
d] wf = 22*2pi/60 * [0.0154/(0.0154+0.0195*0.25^2)]
= 2.135 rad/s
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