Light that has a wavelength of 580 nm is incident on a single slit that is 24.0

Question

Light that has a wavelength of 580 nm is incident on a single slit that is 24.0 mu m wide. Determine the angular location of the first dark fringe that is formed on a screen behind the slit. (Express your answer to three significant figures.) Determine the angular location of the second dark fringe that is formed on a screen behind the slit. (Express your answer to three significant figures.) Determine the angular location of the third dark fringe that is formed on a screen behind the slit. (Express your answer to three significant figures.)

Explanation / Answer

if wavelength is lambda, order of dark fringe is m, slit width is a

then mth order angle T is given by

T=asin(m*lambda/a)

given lambda=580 nm

=580*10^(-9) m

a=24 um=24*10^(-6)

part a:

for m=1,

T=asin(1*580*10^(-9)/(24*10^(-6)))

=0.024169 rad

=1.3848 degrees

in three significant figure, angle=1.38 degrees

Q2.

for m=2,

T=asin(2*580*10^(-9)/(24*10^(-6)))

=2.77 degrees

Q3. for m=3,T=asin(3*580*10^(-9)/(24*10^(-6)))

=4.16 degrees

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