(a) What is the maximum value of the current in the circuit? I max = A (b) What
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Question
(a) What is the maximum value of the current in the circuit?
Imax = A
(b) What are the maximum values of the potential difference across the resistor and the inductor?
VR,max = V
VL,max = V
(c) When the current is at a maximum, what are the magnitudes of the potential differences across the resistor, the inductor, and the AC source?
VR = V
VL = V
Vsource = V
(d) When the current is zero, what are the magnitudes of the potential difference across the resistor, the inductor, and the AC source?
VR = V
VL = V
Vsource = V
Explanation / Answer
a)
We need to use RL analysis in the circuit.
by KVL we can write,
VS - VR – VL = 0
VR = VS[1-e-t/]
VL = VS[e-t/]
Where =R/L
After long time ‘t=infinity’ , VL = VS[e-infinity/] = 0
Hence,
VR = VS
IR = VS
Imax = VS/R = 170/1200 = 0.1417 A
b)
At t=infinity s
VR = VS[1-e-t/]= VS[1-e-infinity/] = VS
VL = VS[e-infinity/] = 0 V
Vsource = VS = 170 V
Thus
VR,max = VS = 170 V
At t= 0 s
VR = VS[1-e-t/]= VS[1-e-0/] = 0 V
VL = VS[e-0/] = VS
Vsource = VS = 170 V
VL,max = VS = 170 V
c)
Current is max at t= infinity,
At t=infinity s
VR = VS[1-e-t/]= VS[1-e-infinity/] = VS = 170 V
VL = VS[e-infinity/] = 0 V
Vsource = VS = 170 V
d)
At t=0s
VR = VS[1-e-t/]= VS[1-e-0/] = 0 V
VL = VS[e-t/] = VS = 170 V
Vsource = VS = 170 V
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