(a) What is the length of a simple pendulum that oscillates with a period of 3.4
ID: 2255515 • Letter: #
Question
(a) What is the length of a simple pendulum that oscillates with a period of 3.4 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?
(b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.4 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?
Explanation / Answer
L on earth=T^2*g/4*pi^2
=9.8*3.4^2/40
=2.832 m
L on mars
=3.7*3.4^2/40
=1.0693 m
b)m on earth=T^2*k/4*pi^2
=5.78 kg
m on mars is same as m on earth
time period is independent of acceleration due to gravity g
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