(a) What is the length of a simple pendulum that oscillates with a period of 3.2

Question

(a) What is the length of a simple pendulum that oscillates with a period of 3.20 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?

(b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.20 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?

mM =?

Explanation / Answer

T=2*pi(L/g)1/2

T1=T2

L1/g1=L2/g2

L2=(L1/g1)*g2

part b)

T=2*pi(m/k)1/2

T1=T2

m1/k1=m2/k2

m2=(m1/k1)*k2

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