(a) What is the length of a simple pendulum that oscillates with a period of 3.0
ID: 1456568 • Letter: #
Question
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?
(b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2?
Explanation / Answer
(a) T = 3s
Time period T = 2pi(L/g)^1/2
on earth gE = 9.8 m/s^2
3 =(2*3.14)(L/9.8)^0.5
LE = 2.236 m
on mars gm = 3.7 m/s^2
3 =(2*3.14)(L/3.7)^0.5
Lm = 0.844 m
(b) k =20 N/m , T =3 s
Time period T = 2pi(m/k)^1/2
3 = (2*3.14)(m/20)^0.5
mE =4.564 kg
mass does nto change due to acceleration
mm = 4.564 kg
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