Question
be made by (22 points total) An AM radio taming eitor to onnecting an inductor, a resistor, and a variable ca have ntenna, as shown in the figure. The inductor xed values. The capacitor changed by a of frequency of the is the same he frequency of the radio station that is to be received. do pts) The frequency of WBLA is 1440 kHz. 1f the value of the inductor in the circuit is 0.300 mH, and the value of resistor is 400 ohms, calculate the value the capacitor needed of to pick up this radio station. citors are costly. while variable resi (8 pts) ble capa tunable circuit instead Varia make this suggests that you should this work? you found in pa f so, using the value of the capa itory the circuit to a frequency of 720 kHz
Explanation / Answer
part a )
at resonance XL = Xc
XL = w*L
Xc = 1/wc
w = 2pif
C = 1/(4*pi^2 * f^2 * L)
given :
L = 0.300 mH = 0.300 x 10^-3 H
f = 1440 kHZ = 1440 x 10^3 Hz
C = 4.07 x 10^-11 F
