READING LIST Google google.com. pg A fast way to browse on iPhone Chrome is a fa

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READING LIST Google google.com. pg A fast way to browse on iPhone Chrome is a fast, simple and secure browser for iP... A technician wraps wire around a tube of length 35 om having a diameter of 7.7 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 565 turns of wire. (a) Find the self-inductance of this solenoid. mH (b) If the current in this solenoid increases at the rate of 5 AVs, what is the self-induced emf in the solenoid? mV Show My Work optional Active Figure 20.4-Induced Current Instructions: Click and drag the magnet through the wire loop to nduce a current, and observe the direction of current flow as indicated by the ammeter needle and by the current arrows within the wire. Click "reverse" to reverse the polarity of the Explore

Explanation / Answer

(a)

formula for self inductance is

L = uo N^2 ( pi d^2/4)/ l = 4 pi * 10^-7 ( 565)^2 ( pi ( 7.7 * 10^-2)^2/4)/0.35 = 5.33 mH

(b)

formula for induced emf is

e = L dI/ dt =-( 5.33 * 10^-3 ) ( 5 A/s) = -26.65 mV

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