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This is my paper that I need to submit, it is about Newton\'s, Force, and Tensio

ID: 1613546 • Letter: T

Question

This is my paper that I need to submit, it is about Newton's, Force, and Tension. Could I please get it checked and corrected if I have any errors? It is supposed to be able to explain the use of force in a way 5th graders could understand. Thanks in advance

Milestone 2
Lab 3 Experiment 2
The Force of the Force and gravity

The force is with you. By force I am referring to the force an object has on it or what we call a Newton not the force Darth Vader uses to lift people off the ground. A Newton is the measurement of force on an object. A Newton can be used to measure how much gravity affects an object or it can be used to measure the force needed to fire a ball out of a cannon.
Measuring forces is very important especially with physics. If we don’t know how much gravitational force is on an object than we would have a very tough time getting planes off the ground. Measuring Newton’s of an object is similar to using a scale. We use spring scales to suspend an object to obtain how many Newton’s are acting on it. Thanks to Newton’s we can even calculate how much force is being used to use the force.
First we will calculate how much force Darth Vader would need to actually lift me off the ground. To do so we will need the formula; F(force)=M(Mass)*A(acceleration). We will use my weight of 68.0389kg and the acceleration to fight gravity which is 9.8m/s2; F=68.0389kg*9.8m/s2, 666.78N=68.0389kg*9.8m/s2. Rounded up that is 667Newton’s needed to accelerate me off the ground. So if I was to come into contact with Darth Vader and he was to lift me in the air using the force he would need at least 667N of upward force to do so.
Now once in the air Darth Vader’s force and held there Darth Vader’s force abilities is going to have tension on it. That is due to my 68.0389kg weight being suspending. Since my acceleration has stopped it will be at zero but the tension is still there. Since the force isn’t real we will have to treat it like myself being suspended by a rope and that is where the tension comes in. Tension is the force transmitted by a pulling motion when being held by a single object such as a rope, this is due to the force of gravity on the object. In this little scenario I will treating the force like a rope so it will have tension, we won’t get into midichlorians and all that oddness.
This is the scenario for the tension, I have met Darth Vader and he just doesn’t like my look so he uses the force to lift me up off the ground. As discussed above the Newton’s needed to force lift me off the ground is 667N. Now we need to know how much tension is being placed on the force to keep me suspended the formula to do so is T= M(mass kg)*G(gravity or 9.8m/s) + M*A(acceleration); T=68.0389kg*9.8m/s2+68.0389kg*0. This equals 666.78N or rounded up 667N. Interestingly this is the same amount of force needed to lift me off the ground at an acceleration of 9.8m/s. This is the amount of acceleration needed to fight gravity of course Darth Vader would not lift me so slowly.
We have now discovered thanks to Newton’s how much force is needed to use the force. This can be very helpful in case you need to lift an object and need to find out how much tension and force is needed. This is something very helpful in instances like rock climbing and you need to know how much tension your rope can handle, because if your rope can’t handle the tension it might be safer to go up against Darth Vader.

Below is the expirment related to the above paper. The expirment is just a reference point and not necessarly related to the paper.

In this experiment, we weighed different objects using two different scales. First was the 5n scale which worked well on the lighter items. The second spring scale was the 10n scale which worked better on the heavier objects. The two different scales working together helped to calibrate each other and have a more accurate reading.
I chose this experiment because it was very interesting to see how the objects effected the two differently weighted scales. While the outcome of the two scales was very similar it was easy to see how the different weights effected the force on the scale. This is also an excellent way to learn about the force of gravity on objects.

Explanation / Answer

Well written, no corrections. Any one would be able to understand easily. Just one change ,unit of acceleration is m/s^2 as you know which you need to correct where you last wrote 9.8.

It got a comical element too that makes it really interesting. All the best.

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