the larger hadron collider(LHC) at cern has a radius of about 4.3 kilometers. we

Question

the larger hadron collider(LHC) at cern has a radius of about 4.3 kilometers. we will assume that iy forms a circle. a proton starts at the north end of the collider and travels the circular ring to the south end

a- what is the distance did the proton travles from the starting point to the end point?
b- what is the desplacment from the starting point to the end point for the proton ?
c- the proton travels at nearly the speed light 3*10^m/s. how long does it take the proton to travel the distance from the north to the south end of the ring?

Explanation / Answer

(a) distance = half length of circular ring
= .r = 3.14 * 4.3 = 13.502 km
(b) displacement = diameter of ring = 2r = 2*.4.3 = 8.6km
(C) taken time = distance /speed = 13.502/3*10^6 =4.50 * 10^-6 sec.

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