Use the figure at the right which represents two point charges Q_1 =-7.88 mu C a

Question

Use the figure at the right which represents two point charges Q_1 =-7.88 mu C and Q_2 = +4.99 mu C, which are separated by a distance of 15.8 cm. Determine the force on Q_2 due to Q_1. a. 7.64 N, to the right b. 9.65 N, to the left. c. 11.2 N, to the left. d. 14.2 N, to the left e. 17.9 N, to the right. f. __ Determine the location where the net electric field due to Q_1 and Q_2 is zero? a. 1.67 cm, right of Q_3. b. 24.7 mm, right of Q_2. c. 31.5 cm, right of Q_2. d. 61.6 cm, right of Q_3. e. 96.5 cm, right of Q_2. f. __

Explanation / Answer

19.

F = kq1q2/r^2

F = 9*10^9*7.88*4.99*10^-12/(15.8*10^-2)^2

F = 14.18 N

since charges are of opposite signs so force will be attractive, which means toward left.

Correct option is D.

20.

suppose at x distance from q2, electric field is zero, then

Enet = kq2/x^2 - kq1/(d + x)^2 = 0

q1/(0.158 + x)^2 = q2/x^2

7.88/(0.158 + x)^2 = 4.99/x^2

Solving above equation

x = 0.6156 m = 61.6 cm

correct option is D.

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