The top of a lake is frozen and a ray of sunlight strikes it at a 45 degree angl

Question

The top of a lake is frozen and a ray of sunlight strikes it at a 45 degree angle of incidence. What is the angle of refraction that is produced, as the sunlight penetrates the ice? 31 degree 1.54 0.87 33 degree Material "A" has a light ray that travels through it o its way to Material "B". As it hits the interface between the two materials, an angle of incidence is formed of 72 degree and an angle of refraction of 56 degree. What is the ratio of the refractive indices (n_1/n_2) of the two materials? 31 degree 1.54 0.87 33 degree An incoming light ray strikes a watery surface at an angle of 43 degree. It also reflects at angle of 43 degree. What is the angle of refraction? 31 degree 1.54 0.87 33 degree What is the refraction index (n_1) of a solid, if the critical angle (theta_c) is 40.5 degree? The solid is surrounded by air. The air has a refraction index (n_2) of 1.000. 31 degree 1.54 0.87 33 degree

Explanation / Answer

1)

From Snell's law

n1/n2 = sin theta2/(sin theta1)

n1 is the refractive index of air = 1.0

n2 is the refractive index of water = 1.31

1/1.31=sin theta2/(sin 45)

theta2=33 degrees

2)

From Snell's law

n1/n2 = sin theta2/(sin theta1)

n1/n2=sin (56)/(sin 72)

n1/n2 = 0.87

3)

n1/n2 = sin theta2/(sin theta1)

n1 is the refractive index of air = 1.0

n2 is the refractive index of water = 1.31

1/1.31=sin theta2/(sin 43)

theta2=31 degrees

4)

n2/n1 = sin theta

sin 40.5 = 1/ n1

n1 = 1.5397 = 1.54

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