When at rest, a proton experiences a net electromagnetic force of magnitude 8.0×

Question

When at rest, a proton experiences a net electromagnetic force of magnitude 8.0×1013 N pointing in the positive x direction. When the proton moves with a speed of 1.7×106 m/s in the positive y direction, the net electromagnetic force on it decreases in magnitude to 7.5×1013 N , still pointing in the positive x direction.

Part A

Find the magnitude of the electric field.

Express your answer using two significant figures.

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Part B

Find the direction of the electric field.

Find the direction of the electric field.

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Part C

Find the magnitude of the magnetic field.

Express your answer using two significant figures.

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Part D

Find the direction of the magnetic field.

Find the direction of the magnetic field.

When at rest, a proton experiences a net electromagnetic force of magnitude 8.0×1013 N pointing in the positive x direction. When the proton moves with a speed of 1.7×106 m/s in the positive y direction, the net electromagnetic force on it decreases in magnitude to 7.5×1013 N , still pointing in the positive x direction.

Part A

Find the magnitude of the electric field.

Express your answer using two significant figures.

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Part B

Find the direction of the electric field.

Find the direction of the electric field.

E = N/C

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Part C

Find the magnitude of the magnetic field.

Express your answer using two significant figures.

positive x direction negative x direction positive y direction negative y direction positive z direction negative z direction

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Part D

Find the direction of the magnetic field.

Find the direction of the magnetic field.

B = T positive x direction negative x direction positive y direction negative y direction positive z direction negative z direction

Explanation / Answer

When at rest, a proton experiences a net electromagnetic force of magnitude 8.0×1013 N pointing in the positive x direction. When the proton moves with a speed of 1.7×106 m/s in the positive y direction, the net electromagnetic force on it decreases in magnitude to 7.5×1013 N , still pointing in the positive x direction.

Part A Find the magnitude of the electric field. Express your answer using two significant figures.
F = q*E
8.0*10^-13 = 1.6 * 10^-19 * E
E = 50 * 10^5 C

Part B Find the direction of the electric field.
In the positive x direction.

Part C Find the magnitude of the magnetic field. Express your answer using two significant figures.

Fe - Fb = 7.5 * 10^-13
Fb = (8.0 - 7.5) * 10^-13 N
Fb = 5 * 10^-14 N

Fb = q* v*B
5 * 10^-14 = 1.6 * 10^-19 * 1.7 * 10^6 * B
B = 0.18 T

Part D Find the direction of the magnetic field.
negative z direction

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