Practice Problem 20.5 Let\'s apply the torque equation to a circular coil of wir

Question

Practice Problem 20.5

Let's apply the torque equation to a circular coil of wire in a magnetic field. The coil has an average radius of 0.0340 m , has 25 turns, and lies in a horizontal plane. It carries a current of 3.50 A in a counterclockwise sense when viewed from above. The coil is in a uniform magnetic field directed toward the right, with magnitude 1.05 T . Find the magnetic moment and the torque on the coil. Which way does the coil tend to rotate?

A) Calculate the torque on the coil when it is placed in a magnetic field along the direction of the axis of the coil.

Explanation / Answer

r = 0.034 m , N = 25 , I = 3.5 A, B = 1.05 T

Torque = MxB = MBsin(theta)

M = NAI

Torque = 25*3.14*0.034^2*3.5*1.05*Sin(90)

= 0.335 N.m

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