In an experiment with cosmic rays, a vertical beam of particles that have change

Question

In an experiment with cosmic rays, a vertical beam of particles that have change of magnitude 3e and mass 12 times the proton mass enters a uniform horizontal magnetic field of 0.250 T and is bent in a semicircle of diameter 95.0 cm, as shown in. Find the speed of the particles. Find the sign of particles' charge. positive negative Is it reasonable to Ignore the gravity force on the particles? reasonable unreasonable How does the speed of the particles as they enter the field compare to their speed as they exit the field? equal nonequal

Explanation / Answer

d = 95 cm => r = 47.5 cm = 0.475 m

m = 12 x 1.67 x 10^-27 = 2 x 10^-26 kg

q = 3e = 3 x 1.6 x 10^-19 = 4.8 x 10^-19 C

We know that, the magnetic force gets balanced by the centripotal force.

Fm = Fc

q v B = m v^2/R

v = q B R/m

v = 4.8 x 10^-19 x 0.25 x 0.475/2 x 10^-26 = 2.85 x 10^6 m/s

Hence, v = 2.85 x 10^6 m/s

Its a negative charge, because of direction of deflection is right.

Reasonable. As the magnetic force is balancing the required centripital force.

The speed remain unchanged, only the path changes.

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