A person stands on a scale in an elevator which is accelerating. The mass of the

Question

A person stands on a scale in an elevator which is accelerating. The mass of the points is 50kg. The elevator accelerates at 3.0 m/s^2 upwards. a) Calculate the normal force that the scale exerts on the person standing on it. b) Assume the scale is calibrated correctly to give the mass of the person in kilograms under normal circumstances (on the ground when there is no acceleration). What mass does the scale give for the person in the accelerating elevator? A highway ramp is being designed. The ramp has the shape of a part of a circular curve. The radius of the curve is 25 meters. The coefficient of friction is .5. What is the maximum speed the car can travel at and still make the curve? A monkey swings back and forth, holding on to a vine. At the highest point, it is 10 meters above the ground. At its lowest point, the monkey is 5 meters above the ground. What is the monkey's speed at the lowest point, ignoring air resistance?

Explanation / Answer

Q6. a. If N= normal force acting on the person

W= weight of the person =mass x g = 50 x 9.8 = 490 N

a= acceleration of the elevator= 3m/s2

applying newton's law of motion

N-W=ma ( as acceleration is upwards, so normal force has to be greater than weight)

so, N = W +ma =490 + 50 x 3= 640 N

so the scale exerts a normal force of 640 N on the person

b. the reading of the scale = normal force/g=640/9.8 = 65.30 kg

all the best in the course work

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