one) M w F section (circle Exam 114. Final Per 16 force he is loop net magnete o
ID: 1622249 • Letter: O
Question
one) M w F section (circle Exam 114. Final Per 16 force he is loop net magnete omentinheloop, the 16 The Same and and the E. 5 A left side and the B tum the top will not of zero, ie. enters a region electric proton moving to the right of E is is not of the seld B. The field is and is most change 1.9. Two long parallel wires carry currents of same same and auments are doubled at the t4 inductor is by evenly winding a is FIboth these foroe vil: the new core, its increase to 4F nin wie ever a B, 2F c decrease to MF Ane number of winding yes core in place of ceramic core E, remain Che replacement 1.10. Three Amperian loops (cow) are drawn among thre cuments of equal magnitude, Rank the loops according to magnitude of B along each, greatest first: E aument through r 1.5 Two parallel wines carry Duments in the same diecson. The force between the wires is: the other A atacave since one is in the magneDe feid of the other mpulsive since one isin he magnetic fold of A 1,2,3 B, 32, 1 C. 1 2 3 C atractive sinon opposite charges attracteach other D, 1 3, 22 D mpublive since ke charges repel each other E. 1 2 3Explanation / Answer
The path can be determined by determining the direction of force on the moving electron. This can be known using the right hand rule. The right hand rule states that: to determine the direction of the magnetic force on a positive moving charge, ƒ, point the thumb of the right hand in the direction of v, the fingers in the direction of B, and a perpendicular to the palm points in the direction of F.
Here, the magnetic field is out of the plane of paper, direction of motion is in the right direction and hence the direction of force is down. Also, it will follow the circular path.
Hence, the correct option is (D)4.
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