Two guys initial who weigh the same are holding onto a massless pole while stand

Question

Two guys initial who weigh the same are holding onto a massless pole while standing on horizontal frictionless ice. The initial positions of the two guys are shown in the figure. The guy on the left starts to pull on the pole. What will happen? a. They will meet at x = -3.0 m. b. They will meet at x = -1.5 m c. They will meet at x = 0 m. d. They will meet at x = +1.5 m. e. They will meet at x = +3.0 m. A 3.0-kg object moving in the positive x direction has a one-dimensional elastic collision with a 7.0-kg object at rest. After the collision the 7.0-kg object has a velocity of 3.0 m/s in the positive x direction. What was the speed of the 3.0 kg object? a. 5.0 m/s b. 7.0 m/s c. 4.5 m/s d. 80 m/s e. 6.0 m/s

Explanation / Answer

9 ans

basing on the concept of system of paraticles

F1d1=F2d2

mg*3=mg*2d

distance they meet d=1.5 m

the correct option is x=-1.5 m

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10 ans

Given that

mass m1=3 kg

mass m2=7 kg

initial velocity u1=1 m/s

initial velocity u2=0 m/s

finial velocity v1=?

finial velocity v2=3 m/s

now we find the finial velocity of 3 kg block

basing on the law of conservation of momentum

m1u1+m2u2=m1v1+m2v2

3*1+7*0=3*v1+7*3

finial velocity v1=6 m/s

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