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rent Documents D Suggested sites DC Council Live E dslbd Department of sm- e DC Code Code of the Di HR e start Do Question 4 of 28 Map EA Sapling Learning A cart for hauling ore out of a gold mine has a mass of 445 kg, including its load. The cart runs along a straight stretch of track that is sloped 4.97 from the horizontal. A donkey, trudging along and to the side of the track, has the unenviable job of pulling the cart up the slope with a 473-N force for a distance of 155 m by means of a rope that is parallel to the ground and makes an angle of 14.1 the track. The coefficient of friction for the cart's wheels on the track is 0.0185. Use g 9.81 m/s2. Find the work that the donkey performs on the cart during this process. 71106.17 14.1 Find the work that the force of gravity rope performs on the cart during the process. Incorrect. 58620.53 97 o Calculate the work done on the track incline cart during the process by friction. horizontal ground Number The force of gravity is in the negative vertical direction. What is the angle between gravity and the displacement? 12517.93 O Previous Give Up & View solution Try Again 0 Exit

Explanation / Answer

You have got the first one right. So I will directly move on to the second one.

The gravitational force on the cart is,

F = mgsin(4.97o) down the slope,

or, F = (445 kg)(9.81 m/s2)sin(4.97o)

or, F = 378.2 N

So work done by the gravity is,

W = F.d = -(377.81 N)(155 m), the work done is negative as force and displacement are in opposite directions

or, W = -58620.52 J

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The force of friction on the cart is,

F = µmgcos(4.97o) down the slope

or, F = (445 kg)(9.8 m/s2)(0.0185)cos(4.97o)

or, F = 80.4 N

So work done by friction is,

W = F.d = -Fd = -(80.4 N)(155 m) the work done is negative as force and displacement are in opposite directions

or, W = -12470.86 J

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification, modification or correction, feel free to ask.....

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