can someone please solve question no. 2 on a paper and please show full work.Tha

Question

can someone please solve question no. 2 on a paper and please show full work.Thank you

2) A toy rocket is launched vertically from ground level (y 0.00 m) time 0.00 s The rocket engine provides constant upward acceleration during the burn at of engine burnout, the rocket has risen phase. At the instant to 72 m and acquired a velocity of 30 m/s. The rocket to rise in unpowered flight, reaches maximum height, and continues is the speed of the rocket upon impact on falls back to the ground with negligible air resistance. What ground?

Explanation / Answer

Total energy of the rocket, E= kinetic energy(KE)+ potential energy(PE)

As there is no air resistance after burn out, the total energy acquired after burnout phase will remain constant.

Let m be the mass of rocket left after burn out and V be the velocity upon impact on ground.

Total energy acquired after burnout= total energy upon impact on ground

or mgh +(1/2)mv² = (1/2)mV²

or 9.81*72 + 0.5*30² = 0.5*V²

or V²= 2312.64

or V= 48 m/s

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