Two toy cars can roll without friction on a horizontal surface. Car A is 5 kg. C
ID: 1626273 • Letter: T
Question
Two toy cars can roll without friction on a horizontal surface. Car A is 5 kg. Car B is 0.5 kg. Both cars start from rest. Equal sized forces are used to push each cart forward for a time of 1 second. After 1 second the force is removed. What is the difference in magnitude of the momenta of the two cars, right after the force is removed?
Choices
A. The momentum of car A(5kg) is EQUAL to that of car B(0.5)
B. The momentum of car A (5kg) is LESS than that car B (0.5)
C. The momentum of car A (5kg) is MORE than that car B (0.5)
D. 5.5 kg m/s
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A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket drops a rock out of it. How long does it take for this rock to hit the ground?
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Car A 5 kg Car B 5 kgExplanation / Answer
from the impulse momentum theorem
Ft = change in momentum
since F and t are constants for both cars
for 5 kg car
Ft = 5kg ( v-0)
Ft = 5v= change in mometum
for 0.5 kg car
Ft = 0.5 v
The momentum of car A (5kg) is MORE than that car B (0.5) since v is constant for both cases due to same force and time
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the distance travelled by the rocket is
s= ut + 1/2 at^2
= 0t + 1/2 ( 165) 8^2
=5280 m
s= ut + 1/2 at^2
5280 = 0 t+ 1/2 (9.8) t^2
t = 32.82 s
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